Cheksiz kamayuvchi geometrik progressiya — 9-sinf Algebra test savollari

1.$b1=4,q=\frac{1}{2}$ bo'lgan cheksiz kamayuvchi geometrik progressiyaning yig'indisini toping.

• A)8
• B)4
• C)2
• D)16

2.$b1=9,q=-\frac{1}{3}$ bo'lgan cheksiz kamayuvchi geometrik progressiyaning yig'indisini toping.

• A)6,75
• B)27
• C)9
• D)3

3.0,3 + 0,03 + 0,003 + ... cheksiz kamayuvchi geometrik progressiya yig'indisini oddiy kasr shaklida toping.

• A)$\frac{1}{3}$
• B)$\frac{3}{10}$
• C)$\frac{1}{9}$
• D)3

4.Cheksiz kamayuvchi geometrik progressiyada S = 10, b1 = 4. q ni toping.

• A)0,6
• B)0,4
• C)2,5
• D)0,1

5.$1+\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+$ ... cheksiz kamayuvchi geometrik progressiya yig'indisini toping.

• A)2
• B)1
• C)4
• D)$\frac{1}{2}$

6.Cheksiz kamayuvchi geometrik progressiyaning yig'indisi formulasini ko'rsating.

• A)S = b1/(1-q)
• B)S = b1·q
• C)S = b1(1-q)
• D)S = b1/(1+q)

7.Cheksiz kamayuvchi geometrik progressiya bo'lishi uchun q qanday shartni qanoatlantirishi kerak?

• A)|q| < 1 (q ≠ 0)
• B)|q| > 1
• C)q = 1
• D)q = 0

8.$b1=6,q=\frac{1}{3}$ bo'lgan cheksiz kamayuvchi geometrik progressiyaning yig'indisini toping.

• A)9
• B)6
• C)3
• D)18

9.$b1=2,q=\frac{1}{4}$ bo'lgan cheksiz kamayuvchi geometrik progressiyaning yig'indisini toping.

• A)$\frac{8}{3}$
• B)$\frac{2}{3}$
• C)$\frac{3}{8}$
• D)4

10.0,5 + 0,25 + 0,125 + ... cheksiz kamayuvchi geometrik progressiya yig'indisini toping.

• A)1
• B)0,5
• C)2
• D)0,75