Geometrik progressiya dastlabki n ta hadining yig'indisi — 9-sinf Algebra test savollari

Bu mavzuda 15 ta test savoli bor. Quyida 10 ta namuna — to'liq test va javoblar kaliti ro'yxatdan o'tgandan keyin ochiladi.

1.b1 = 3, q = 2 bo'lgan geometrik progressiyaning dastlabki 5 ta hadi yig'indisini toping.
- A)93
- B)96
- C)90
- D)63
2.b1 = 1, q = 3 bo'lgan geometrik progressiyaning dastlabki 4 ta hadi yig'indisini toping.
- A)40
- B)80
- C)27
- D)121
3.2 + 4 + 8 + 16 + 32 yig'indisini geometrik progressiya yig'indisi formulasi bilan toping.
- A)62
- B)60
- C)64
- D)58
4.b1 = 5, q = -2 bo'lgan geometrik progressiyaning dastlabki 4 ta hadi yig'indisini toping.
- A)-25
- B)25
- C)-15
- D)15
5.b1 = 1, q = 2, Sn = 127 bo'lgan geometrik progressiyada n ni toping.
- A)7
- B)6
- C)8
- D)5
6.Geometrik progressiya yig'indisining formulasini ko'rsating (q ≠ 1).
- A) $S n = b 1 (q^{n} - 1) / (q - 1)$
- B)Sn = b1· $q^{n}$
- C)Sn = b1·n
- D)Sn = b1/(q-1)
7.b1 = 2, q = 5 bo'lgan geometrik progressiyaning dastlabki 3 ta hadi yig'indisini toping.
- A)62
- B)60
- C)58
- D)64
8.1 + 2 + 4 + 8 + 16 yig'indisini toping.
- A)31
- B)32
- C)30
- D)16
9.b1 = 3, q = 1 bo'lgan geometrik progressiyaning dastlabki 6 ta hadi yig'indisini toping.
- A)18
- B)3
- C)6
- D)36
10.Geometrik progressiya yig'indisi formulasida q = 1 bo'lgan holda Sn qanday hisoblanadi?
- A)Sn = b1·n
- B)Sn = b1/(1-n)
- C)Sn = 0
- D)Sn = b1

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Geometrik progressiya dastlabki n ta hadining yig'indisi — 9-sinf Algebra test savollari

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